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How are the pressure, volume and temperature of a gas related?

The gas laws: use Boyle's law, Charles's law, Gay-Lussac's law and the combined gas law to relate the pressure, volume and temperature of a gas.

A focused Virginia SOL Chemistry answer on the gas laws under CH.4: Boyle's law (pressure and volume), Charles's law (volume and temperature), Gay-Lussac's law (pressure and temperature), and the combined gas law, with worked calculations and the need for Kelvin temperature.

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  1. What this topic is asking
  2. Boyle's law
  3. Charles's law
  4. Gay-Lussac's law and the combined gas law
  5. Try this

What this topic is asking

Standard CH.4 asks you to relate the pressure, volume and temperature of a gas using the gas laws. Virginia expects you to apply Boyle's law, Charles's law, Gay-Lussac's law and the combined gas law to calculate an unknown quantity. The recurring rule is that temperature must be in kelvin, and the calculations are one-step rearrangements.

Boyle's law

This makes sense from kinetic molecular theory: squeezing the gas into a smaller volume makes the particles hit the walls more often, raising the pressure. Doubling the pressure halves the volume. Boyle's law has no temperature term because temperature is held constant.

Charles's law

Heating a gas makes its particles move faster and push outward, so the gas expands to keep the pressure constant. Because the relationship is direct, doubling the Kelvin temperature doubles the volume. This is why temperature must be in kelvin: using Celsius would give a wrong ratio (and absurd results near 0C0\,^{\circ}\text{C}).

Gay-Lussac's law and the combined gas law

Gay-Lussac's law holds the volume constant and relates pressure to Kelvin temperature directly: P1T1=P2T2\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2}. Heating a gas in a rigid container raises the pressure as the particles strike the walls harder and more often.

The combined gas law merges all three into one relationship for a fixed amount of gas:

P1V1T1=P2V2T2\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

If one of pressure, volume or temperature is held constant, it cancels from both sides and the combined law reduces to Boyle's, Charles's or Gay-Lussac's law. This makes the combined gas law the one formula to remember: write it out, cross out whatever the question holds constant, and solve the rest. The subscript 11 values are the starting conditions and the subscript 22 values are the final conditions, so a common, safe routine is to list P1P_1, V1V_1, T1T_1, P2P_2, V2V_2 and T2T_2, convert any Celsius temperatures to kelvin, identify the unknown, and rearrange for it before substituting.

Try this

Q1. A gas at 1.01.0 atm and 4.04.0 L is compressed to 2.02.0 L at constant temperature. Find the new pressure. [2 points]

  • Cue. Boyle's law: P2=(1.0)(4.0)2.0=2.0P_2 = \dfrac{(1.0)(4.0)}{2.0} = 2.0 atm.

Q2. Why must temperature be in kelvin for the gas laws? [1 point]

  • Cue. The laws use absolute temperature; the Kelvin scale starts at absolute zero, so ratios of temperature are only meaningful in kelvin.

Exam-style practice questions

Practice questions written in the style of VDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SOL (multiple choice)1 marksAt constant temperature, if the volume of a gas decreases, its pressure will (A) increase (B) decrease (C) stay the same (D) drop to zero
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The answer is (A) increase.

Boyle's law states that pressure and volume are inversely related at constant temperature: P1V1=P2V2P_1 V_1 = P_2 V_2. As volume decreases, the same number of particles strike a smaller area more often, so pressure increases. Squeezing a gas into half the volume doubles its pressure.

The trap is thinking pressure and volume change in the same direction; they are inversely related, so one rises as the other falls.

SOL (tech-enhanced, fill in the blank)3 marksA gas occupies 4.04.0 L at 2.02.0 atm. The volume is changed to 2.02.0 L at constant temperature. (a) State which gas law applies. (b) Calculate the new pressure.
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A 3-point Boyle's-law calculation.

(a) Gas law (1 point): Boyle's law (constant temperature, pressure and volume).
(b) Calculation (2 points): P1V1=P2V2P_1 V_1 = P_2 V_2, so P2=P1V1V2=(2.0 atm)(4.0 L)2.0 L=4.0P_2 = \dfrac{P_1 V_1}{V_2} = \dfrac{(2.0\ \text{atm})(4.0\ \text{L})}{2.0\ \text{L}} = 4.0 atm.

Markers reward identifying Boyle's law and rearranging correctly. Halving the volume doubles the pressure, which matches the inverse relationship.

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