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How do you use a confidence interval for a difference of two means to justify a claim?

Topic 7.7 Justifying a Claim About the Difference of Two Means Based on a Confidence Interval: use a two-sample (or paired) mean interval to judge whether the means differ and to assess claims about the size and direction of the difference.

A focused answer to AP Statistics Topic 7.7, on using a two-sample or paired mean confidence interval to judge whether two means differ and to assess claims about the size and direction of the difference, with worked justifications.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. The zero-check for two means
  3. Judging size-of-difference claims
  4. Confidence level, sample size, and decisiveness
  5. Try this

What this topic is asking

The College Board (Topic 7.7) wants you to use a two-sample (or paired) mean interval to justify a claim: judge whether the means differ (does the interval contain 00?), and evaluate claims about the size and direction of the difference, accounting for confidence level and sample size.

The zero-check for two means

This is the same plausible-value reasoning as for a single mean, with the relevant null value being 00 (equal means). The sign of an interval that excludes 00 gives the direction of the difference, so always state the subtraction order ("group 11 minus group 22"). For paired data, the interval is for the mean difference μd\mu_d, and the zero-check asks whether μd=0\mu_d = 0 (no average change) is plausible.

Judging size-of-difference claims

A magnitude claim, "the new method lowers the mean by at least 33," must be judged against the entire interval, not the point estimate. If part of the interval falls short of the claimed size (here, includes values greater than 3-3), then a smaller effect is still plausible and the claim is not established, even if the observed difference meets it. Only if the whole interval satisfies the claim is it supported. As always, the interval, the set of plausible differences, carries the justification, not the single observed difference. Distinguishing "is there a difference?" from "is the difference at least this big?" is a recurring free-response discriminator.

Confidence level, sample size, and decisiveness

A higher confidence level widens the interval, which can pull a once-decisive interval back across 00 and weaken a difference conclusion; a lower level narrows it (more decisive, correct less often). A larger sample in either group narrows the interval by shrinking the standard error, sharpening conclusions about both the existence and size of a difference. These trade-offs mirror the one-sample case; exam questions ask you to predict the direction of each change and explain the mechanism.

Try this

Q1. A 95%95\% interval for μ1μ2\mu_1 - \mu_2 is (7.0,2.0)(-7.0, -2.0). What does it say? [1 point]

  • Cue. Entirely below 00: convincing evidence μ1<μ2\mu_1 < \mu_2 (group 11 mean is smaller).

Q2. For paired data, what does the zero-check ask? [1 point]

  • Cue. Whether μd=0\mu_d = 0 (no average difference) is plausible; if 00 is outside the interval, there is evidence of a real mean change.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2017 (style)1 marksSection I (multiple choice). A 95%95\% confidence interval for μ1μ2\mu_1 - \mu_2 is (1.5, 4.0)(-1.5,\ 4.0). Based on this interval, there is (A) convincing evidence μ1>μ2\mu_1 > \mu_2 (B) convincing evidence μ1<μ2\mu_1 < \mu_2 (C) no convincing evidence the means differ (D) proof the means are equal
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The correct answer is (C).

The interval (1.5,4.0)(-1.5, 4.0) contains 00, so 00 (no difference) is a plausible value of μ1μ2\mu_1 - \mu_2; there is no convincing evidence the two means differ.

(A) and (B) require the whole interval above or below 00. (D) overstates: an interval never proves equality.

AP 2021 (style)4 marksSection II (free response). A 90%90\% confidence interval for μnewμold\mu_{\text{new}} - \mu_{\text{old}}, the difference in mean processing time (seconds) for a new versus old system, is (4.5, 0.5)(-4.5,\ -0.5). (a) Justify in context whether there is convincing evidence the new system is faster (smaller mean time). (b) An engineer claims the new system cuts mean time by at least 33 seconds. Justify whether the interval supports this. (c) Explain how a larger sample would change the interval and the justifications.
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A 4-point justification question on a difference.

(a) (2 points) The entire interval (4.5,0.5)(-4.5, -0.5) lies below 00, so 00 is not a plausible difference; there is convincing evidence that μnew<μold\mu_{\text{new}} < \mu_{\text{old}}, i.e. the new system has a smaller mean processing time (is faster).
(b) (1 point) "Cuts by at least 33 seconds" means μnewμold3\mu_{\text{new}} - \mu_{\text{old}} \le -3. The interval includes values above 3-3 (such as 1-1), so a smaller reduction is still plausible; the interval does not establish a cut of at least 33 seconds.
(c) (1 point) A larger sample shrinks the standard error, narrowing the interval; this could exclude more values, making any conclusion about the size of the difference more decisive (without changing the center on average).

Markers reward the zero-check for part (a), reading the whole interval against 3-3 for part (b), and linking larger samples to a narrower interval.

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