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How do you use a confidence interval for a mean to justify a claim about the population mean?

Topic 7.3 Justifying a Claim About a Population Mean Based on a Confidence Interval: use a one-sample mean interval to judge whether a claimed mean is plausible, and explain how confidence level and sample size affect the interval.

A focused answer to AP Statistics Topic 7.3, on using a one-sample t-interval to judge whether a claimed value of the population mean is plausible, and explaining how confidence level and sample size change the interval, with worked justifications.

Generated by Claude Opus 4.89 min answer

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  1. What this topic is asking
  2. The plausible-values logic for means
  3. Directional claims need the whole interval
  4. How confidence level and sample size move the interval
  5. Try this

What this topic is asking

The College Board (Topic 7.3) wants you to use a one-sample mean interval to justify a claim about μ\mu: decide whether a claimed value is plausible (inside the interval?), assess directional claims against the whole interval, and explain how confidence level and sample size change the interval and the conclusion.

The plausible-values logic for means

This is the same reasoning as for proportions, now applied to a mean. You do not need a separate significance test to assess one claimed value: check whether it lies inside the interval. A two-sided t-test at α=1C\alpha = 1 - C reaches the same verdict, the duality that links Topic 7.3 to the testing topics that follow.

Directional claims need the whole interval

A claim like "μ\mu is less than 505505" must be checked against the entire interval, not the point estimate xˉ\bar{x}. If any part of the interval reaches or exceeds 505505, then a mean of 505505 or more is still plausible, so the claim is not established, even when xˉ<505\bar{x} < 505. Only if the whole interval lies below 505505 is "μ<505\mu < 505" supported. The same applies to "at least," "more than," and "between" claims: the interval, the set of plausible means, carries the justification, never the single observed mean. This is one of the most reliable free-response discriminators in the unit.

How confidence level and sample size move the interval

Raising confidence widens the interval (more often correct, less precise), so more claimed values become plausible and fewer can be ruled out, a less decisive justification. A larger sample shrinks the standard error s/ns/\sqrt{n}, narrowing the interval (precision improving with n\sqrt{n}), so more values fall outside and can be excluded, a more decisive justification. A larger sample changes precision, not the center on average, so it does not bias the estimate toward any claim. Questions routinely ask you to predict and explain the direction of these effects.

Try this

Q1. A 90%90\% interval for μ\mu is (12.1,13.9)(12.1, 13.9). Is a claimed mean of 1313 plausible? [1 point]

  • Cue. Yes; 1313 is inside the interval, so it is a plausible value of μ\mu.

Q2. Holding confidence fixed, how does a larger sample affect the ability to rule out a claimed mean? [1 point]

  • Cue. It narrows the interval, so more values fall outside and can be ruled out; the justification becomes more decisive.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2017 (style)1 marksSection I (multiple choice). A 95%95\% confidence interval for a population mean is (48.2, 53.8)(48.2,\ 53.8). A claim states the mean is 5050. Based on the interval, the claim is (A) not plausible (B) plausible, because 5050 lies within the interval (C) proven true (D) impossible to evaluate
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The correct answer is (B).

Because 5050 lies inside the 95%95\% interval (48.2,53.8)(48.2, 53.8), it is a plausible value of the population mean; the data are consistent with the claim.

(A) is wrong: 5050 is inside, hence plausible. (C) overstates: an interval never proves a value. (D) is wrong: the interval is exactly the tool for this judgement.

AP 2021 (style)4 marksSection II (free response). A 99%99\% confidence interval for the mean weight μ\mu (in grams) of a product, from a random sample of n=40n = 40, is (494, 506)(494,\ 506). (a) The packaging claims a mean weight of 500500 grams. Justify in context whether the interval supports the claim. (b) A regulator claims the mean is below 505505 grams. Justify whether the interval supports this. (c) Explain how a 90%90\% interval would differ and what it would mean for the justifications.
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A 4-point justification question.

(a) (1 point) 500500 lies inside (494,506)(494, 506), so 500500 grams is a plausible value of μ\mu; the interval supports the packaging claim.
(b) (2 points) "Below 505505" means μ<505\mu < 505. The interval includes values above 505505 (up to 506506), so a mean of 505505 or more is still plausible; the interval does not establish that the mean is below 505505 grams.
(c) (1 point) A 90%90\% interval uses a smaller tt^{*}, so it is narrower, centered on the same xˉ=500\bar{x} = 500. A narrower interval could exclude more values, making the justifications more decisive (and might place the whole interval below 505505).

Markers reward the inside/outside test for part (a), reading the whole interval against 505505 for part (b), and linking lower confidence to a narrower interval.

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